|Score:||(2.95 in 22 votes)|
`` Scriptol version of 99 bottles of beer `` by Sandrine Takis - Public Domain text bottle(int n) if n = 0 return "no more bottles of beer" return text(n) + " bootle" + plural(n) + " of beer" text b1 for int i in 99 -- 0 step -1 b1 = bottle(i) if i > 0 print b1, "on the wall,", b1 + "," print "take one down, pass it around," print bottle(i - 1), "on the wall." /if /for
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